12/29/2022 0 Comments Iza calzado topless![]() ![]() " Janella once again proves to us what the power she holds! She never fails to amaze me with her acting skills and fierceness!! Shettt I am now a Valentina apologist," one user wrote. ![]() Many users posted that they would be a "Valentina apologist". In a surprising turn of events, instead of De Leon's Darna being the hot topic among Twitter users, it's actually Salvador's portrayal of Valentina that's being talked about and praised. ![]() But she later finds out that the responsibility may come a little bit too soon as her mother perishes at the hands of the enemy. Sobrang lakas maka-WONDER WOMAN!Īfter finding out that her mother is secretly a superhero, Narda is then tasked with being the next protector of the white stone -the source of Darna's powers. Sana magkaroon ng back story ang Unang Darna at si Miss ang bida. I can also see the AMIHAN we loved back then. Based on the trailer, I think she really owned it. Iza Calzado is, indeed, a perfect DARNA tbh. Sobrang lakas maka-WONDER WOMAN!" another user wrote. Sana magkaroon ng back story ang Unang Darna at si Miss Iza Calzado ang bida. But it just feels so great to see Iza Calzado as the first Darna in this remake," he said.Īngel Locsin did a perfectly great job as Darna before but I think Iza Calzado would’ve done just as great as Angel Locsin for the role of Darna.īut it just feels so great to see Iza Calzado as the first Darna in this remake. "Angel Locsin did a perfectly great job as Darna before, but I think Iza Calzado would’ve done just as great as Angel Locsin for the role of Darna. One user shared how he thinks Calzado would do just as great as Locsin in playing the character. This was because of the requirement that Calzado had to lose weight for the role. Twitters users took to the social media platform to share how Calzado "owned" the role of Darna and recalled how she was originally going to be cast as the superhero back in its 2005 series by GMA Network, but the role went to Angel Locsin instead. ![]()
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